Find three consecutive numbers such that twice the first, three times the second

Question

Find three consecutive numbers such that twice the first, three times the second and four times the third together make 191.

Options:

A . 20, 21, 22

B . 19, 20, 21

C . 21, 22, 23

D . 22, 23, 24

Answer: Option A
Answer: (a)Numbers = x, x +1 and x + 22x + 3x + 3 + 4x + 8 = 1919x = 191 – 11 = 180x = 20∴ Numbers = 20, 21 and 22

Was this answer helpful ?

Next Question

Chapter 1 - GLOBAL STEEL SCENARIO & INDI Part 1 : (13-04-2024) INDUSTRY AND COMPANY AWARENESS (ICA)

Direction Sense Test Part 1 Reasoning (Hindi)

Chapter 1 - RMHP / OHP / OB & BP Part 1 : (14-02-2024) GPOE

Cube & Cuboid Part 1 Reasoning (Hindi)

Data Interpretation (DI) Basic Concept Reasoning (Hindi)

Counting Figures Part 1 Counting Of Straight Lines Reasoning (Hindi)

Sail E0 free webinar Webinars

Real Numbers Part 7 Class 10 Maths

Real Numbers Part 1 Class 10 Maths

Polynomials Part 1 Class 10 Maths

Chapter 3.1 : Overview of Finance & Acco Chapter 3 : Finance & Accounts SAIL E0 - GFM 2024

Chapter 2.1 : Overview Chapter 2 : Materials Management SAIL E0 - GFM 2024

Chapter 1.1 : Personnel Functions- An ov Chapter 1 : Personnel Management SAIL E0 - GFM 2024

GPOE / GPA Combined 1 Free CBT Mock Test SAIL E0 2024

CBT Mixed Test 1 GPOE/GPA SAIL E0 2024