Question
Find the value of 1−tan2 30∘1+tan2 30∘.
Answer: Option A
:
A
We know thattan30∘=1√3.
⇒1−tan230∘1+tan230∘=1−(1√3)21+(1√3)2
=1−(13)1+(13)
=3−13+1
=24 = 12=0.5
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:
A
We know thattan30∘=1√3.
⇒1−tan230∘1+tan230∘=1−(1√3)21+(1√3)2
=1−(13)1+(13)
=3−13+1
=24 = 12=0.5
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