Find the least number which when divided by 35 and 11 leaves a remainder of 1 in each case.
Options:
A . 384
B . 391
C . 388
D . 397
E . 386
Answer: Option E
The least number which when divided by different divisors leaving the same remainder in each case= LCM(different divisors) + remainder left in each case.Hence the required least number = LCM(35, 11) + 1 = 386.
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