Question
Find the area enclosed by the curve x=y2+2, ordinates y = 0 & y = 3 and the Y - axis.
Answer: Option C
:
C
We have seen that if g(y)≥0 for yϵ [c, d] then the area bounded by curve x = g(y) and y-axis between abscissa y = c and y = d is ∫d(y=c)g(y)dy .
We'll use the same concept here. Here the curve given is
x=y2+2 and c = 0 &d=3.So,g(y)≥0∀xϵ(0,3)
Let the area enclosed be A.
A=∫30(y2+2)dy.
A=(y33+2y)|30A=9+6−0A=15
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:
C
We have seen that if g(y)≥0 for yϵ [c, d] then the area bounded by curve x = g(y) and y-axis between abscissa y = c and y = d is ∫d(y=c)g(y)dy .
We'll use the same concept here. Here the curve given is
x=y2+2 and c = 0 &d=3.So,g(y)≥0∀xϵ(0,3)
Let the area enclosed be A.
A=∫30(y2+2)dy.
A=(y33+2y)|30A=9+6−0A=15
Was this answer helpful ?
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