Question
Answer: Option A
:
A
EF divides the rectangle ABCDinto two trapeziums.
Area of trapezium ABFE
=12×(Sumofparallelsides)×(Distancebetweenthem
=12×(AE+BF)×AB
=12×(1+2)×4
=12×3×4=6cm2
Area of trapezium CDEF =12×(FC+ED)×CD
=12×(1+2)×4
=12×3×4=6cm2
Area of both the trapeziums are equal.
∴ EF divides the rectangle ABCD in two equal parts and the area of both the parts are 6cm2.
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:
A
EF divides the rectangle ABCDinto two trapeziums.
Area of trapezium ABFE
=12×(Sumofparallelsides)×(Distancebetweenthem
=12×(AE+BF)×AB
=12×(1+2)×4
=12×3×4=6cm2
Area of trapezium CDEF =12×(FC+ED)×CD
=12×(1+2)×4
=12×3×4=6cm2
Area of both the trapeziums are equal.
∴ EF divides the rectangle ABCD in two equal parts and the area of both the parts are 6cm2.
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