Construction of a ΔA′C′B similar to ΔACB is shown in the figure below, which condition is used to construct A′C′ ||AC?
Options:
A .
Corresponding angles are equal
B .
Alternate interior angles are equal
C .
Co-interior angles are supplementary
D .
Perpendicular bisector theorem
Answer: Option A : A Here we construct A′C′||AC by making ∠A′C′B=∠ACB and we used the corresponding angle property (if corresponding angles of two lines are equal, then the lines are parallel).
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