Question
Consider steady-state equimolar counterdiffusion through the converging-diverging tube. Given: r₁=1cm; r₂=2cm; Nᴀ=10⁻⁶ kmol/m².s at the vessel 1 end of the tube. The rate of transport of B at the vessel 2 end of the tube is
Answer: Option B
Answer: (b).2.5*10⁻⁷ kmol/s, towards vessel 1
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Answer: (b).2.5*10⁻⁷ kmol/s, towards vessel 1
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