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Capacity of a cylindrical vessel is 25.872 litres. If the height of the cylinder is three times the radius of its base, what is the area of the base ?
Options:
A .  336 cm2
B .  616 cm2
C .  1232 cm2
D .  Cannot be determined
E .  None of these
Answer: Option B
Volume of cylinder :
$$\eqalign{
& = 25.872\,{\text{litres}} \cr
& = \left( {25.872 \times 1000} \right){\text{c}}{{\text{m}}^{\text{3}}} \cr
& = 25872\,{\text{ c}}{{\text{m}}^3} \cr} $$
Let the radius of the base of the cylinder be r cm
Then, height = (3r) cm
$$\eqalign{
& \therefore \frac{{22}}{7} \times {r^2} \times \left( {3r} \right) = 25872 \cr
& \Rightarrow {r^3} = \frac{{25872 \times 7}}{{66}} \cr
& \Rightarrow {r^3} = 2744 \cr
& \Rightarrow r = \root 3 \of {2744} \cr
& \Rightarrow r = 14 \cr} $$
Hence, area of the base :
$$\eqalign{
& = \pi {r^2} \cr
& = \left( {\frac{{22}}{7} \times 14 \times 14} \right){\text{ c}}{{\text{m}}^2} \cr
& = 616\,{\text{ c}}{{\text{m}}^2} \cr} $$

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