Calculate the volume occupied by 16 gram O 2 at 300 K and 8.31 Mpa if P c V R T c = 3 8 a n d P r V r T r = 2.21 ⟮ : R = 8.314 M p a K − m o l ⟯ Options: A . &nbsp124.31 lit B . &nbsp124.31 mL C . &nbsp248.62 mL D . &nbsp248.62 L

Answer: Option B : B P V m R T = 3 8 × 2.21 ; V m = ⟮ 3 8 × 2.21 ⟯ × R T P V m = 3 8 × 2.21 × 8.314 × 300 8.314 = 248.625 m L V O 2 = 16 32 × 248.625 = 124.31 m L

Calculate the volume occupied by 16 gram O2 at 300 K and 8.31 Mpa if PcVRTc=38&#

Question

Calculate the volume occupied by 16 gram

O_{2}

at 300 K and 8.31 Mpa if

\frac{P_{c} V}{R T_{c}} = \frac{3}{8} a n d \frac{P_{r} V_{r}}{T_{r}} = 2.21 ⟮ : R = 8.314 \frac{M p a}{K - m o l} ⟯

Options:

A . 124.31 lit

B . 124.31 mL

C . 248.62 mL

D . 248.62 L

Answer: Option B
:
B

\frac{P V_{m}}{R T} = \frac{3}{8} \times 2.21; V_{m} = ⟮ \frac{3}{8} \times 2.21 ⟯ \times \frac{R T}{P}

V_{m} = \frac{3}{8} \times 2.21 \times \frac{8.314 \times 300}{8.314} = 248.625 m L

V_{O_{2}} = \frac{16}{32} \times 248.625 = 124.31 m L

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