Question
At which of the following temperature the molecules of a gas have twice the average kinetic energy of molecules at `20^circ C` :
Answer: Option A
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We know that E `prop` T
or ` E_1/E_2 = T_1/T_2`
Here `E_1 = E`
`E_2 = 2E`
`T_1 = 20 + 273 = 293 K`
`:.` `(E)/(2E) = 293/_2`
or `T_2 = 586 K`
Hence , `T_2 = 596 - 273 = 313^circ C`
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