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Question
Ashu was born on August 19, 1992, What day of the week was the born?
Options:
A .  Sunday
B .  Monday
C .  Tuesday
D .  Wednesday
Answer: Option D
Answer: (d)
19th August 1992 means,
1991 complete years + First 7 months of 1992 + 19 days of August
Number of odd days in 1600 years = 0
Number of odd days in 300 yrs = 1
Number of odd days in 91 yrs (22 leap year + 69 non-leap years)
= 22 × 2 + 69 × 1
= 44 + 69 113
= 7 × 16 + 1 = 1 odd day
From 1st January, 1992 to 19th August, 1992
Number of odd days in 1992,
January
3
February
1
March
3
April
2
May
3
June
2
July
3
August
5
= 3 + 1 + 3 + 2 + 3 + 2 + 3 + 5
= 22 = 7 × 3 + 1
= 1 odd day
∴ Number of odd days till 19th August, 1992 = 0 + 1 + 1 + 1 = 3
So, the required day was Wednesday.

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