Answer : Option A
Explanation :
Let the sum be x
Simple interest on x for 2 years = Rs.2000
$MF#%\text{Simple interest = }\dfrac{\text{PRT}}{100}\\\\ 2000 = \dfrac{x \times \text{R} \times 2}{100}\\\\ \Rightarrow x\text{R} = 100000 \quad \color{#F00}{\text{--- (1)}}$MF#%
Compound Interest on x for 2 years = 2400
$MF#%\text{P}\left(1 + \dfrac{\text{R}}{100}\right)^\text{T} - \text{P} = 2400\\\\ x\left(1 + \dfrac{\text{R}}{100}\right)^2 - x = 2400\\\\ x\left(1 + \dfrac{\text{2R}}{100} + \dfrac{\text{R}^2}{10000}\right) - x = 2400\\\\ x\left(\dfrac{\text{2R}}{100} + \dfrac{\text{R}^2}{10000}\right) = 2400\\\\ \dfrac{2x\text{R}}{100} + \dfrac{x\text{R}^2}{10000} = 2400 \quad \color{#F00}{\text{--- (2)}}\\\\$MF#%
Substituting the value of xR from (1) in (2) ,we get
$MF#%\dfrac{2 \times 100000}{100} + \dfrac{100000 \times \text{R}}{10000} = 2400\\\\ 2000 + 10 \text{R} = 2400\\\\ 10 \text{R} = 400\\\\ \text{R} = 40\%$MF#%
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