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Question
According to combination rule, if the total number of outcomes are 'r' and distinct outcome collection is 'n' then combinations are calculated as
Options:
A .  n! ⁄ r!(n - r)!
B .  n! ⁄ r!(n + r)!
C .  r! ⁄ n!(n - r)!
D .  r! ⁄ n!(n + r)!
Answer: Option A
Answer: (a).n! ⁄ r!(n - r)!

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