ABC is an isosceles triangle where AB = AC which is circumscribed about a circle

Question

ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true?

Options:

A . PB = PC

B . PB > PC

C . PB < PC

D . PB = $$\frac{1}{2}$$ PC

Answer: Option A

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