Lakshya Education MCQs

Question: A young girl counted in the following way on the fingers of her left hand. She started calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5, then reversed direction, calling the ring finger 6, middle finger 7, index finger 8, thumb 9 and then back to the index finger for 10, middle finger for 11, and so on. She counted upto 1994. She ended on her
Options:
A.thumb
B.index finger
C.middle finger
D.ring finger
Answer: Option B

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More Questions on This Topic :

Question 1. The numbers 1, 2, 3, 4, ......, 1000 are multiplied together. The number of zeros at the end (on the right) of the product must be :
  1.    30
  2.    200
  3.    211
  4.    249
Answer: Option D
Question 2. The unit's digit of 132003 is :
  1.    1
  2.    3
  3.    7
  4.    9
Answer: Option C
Question 3. The number 89715938* is divisible by 4. The unknown non-zero digit marked as * will be :
  1.    2
  2.    3
  3.    4
  4.    6
Answer: Option C
Question 4. A number when divided by 195 leaves a remainder 47. If the same number is divided by 15, the remainder will be :
  1.    1
  2.    2
  3.    3
  4.    4
Answer: Option B
Question 5. The number of prime factors in the expression 610 × 717 × 1127 is equal to :
  1.    54
  2.    64
  3.    71
  4.    81
Answer: Option B
Question 6. If n is a natural number and n = $${p_1}^{{x_1}}$$   $${p_2}^{{x_2}}$$   $${p_3}^{{x_3}}$$ where p1, p2, p3 are distinct prime factors, then the number of prime factors for n is :
  1.    $${x_1} + {x_2} + {x_3}$$
  2.    $${x_1} \times {x_2} \times {x_3}$$
  3.    $$\left( {{x_1} + 1} \right)\left( {{x_2} + 1} \right)\left( {{x_3} + 1} \right)$$
  4.    None of these
Answer: Option B

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