Question
A thin uniform circular ring is rolling down an inclined plane of inclination 30∘ without slipping. Its linear acceleration along the inclined plane will be
Answer: Option C
:
C
a=gsinθ1+k2R2=gsin30∘1+1=g4 [Ask2R2=1andθ=30∘]
Was this answer helpful ?
:
C
a=gsinθ1+k2R2=gsin30∘1+1=g4 [Ask2R2=1andθ=30∘]
Was this answer helpful ?
Submit Solution