A tabulator while calculating the average marks of 100 students of an examination, by mistake enters 68, instead of 86 and obtained the average as 58; the actual average marks of those students is
Options:
A . 57.82
B . 58.18
C . 57.28
D . 58.81
Answer: Option B Answer: (b)Difference = 86 – 68 = 18 ∴ Actual average = 58 + $18/100$ = 58.18 Aliter : Using Rule 26, The correct average will be = m +${\text"(a-b)"}/ \text"n"$. Here, n = 100, m = 58 a = 86, b = 68 Correct Average = m + ${\text"(a - b)"}/\text"n"$= 58 +${(86 -68)}/100$= 58 + $18/100$= 58 + 0.18 = 58.18
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