A sum of money lent at simple interest amounts to Rs.880 in 2 years and to Rs.920 in 3 years. The sum of money (in rupees) is
Options:
A . 760
B . 700
C . 800
D . 784
Answer: Option C Answer: (c)If the principal be x and rate of interest be r% per annum, thenSI after 1 year = 920 - 880 = Rs.40SI after 2 years = Rs.80880 = x + 80x = Rs.(880 - 80) = Rs.800Using Rule 12If certain sum P amounts to Rs. $A_1$ in $t_1$ years at rate of R% and the same sum amounts to Rs. $A_2$ in $t_2$ years at same rate of interest R%. Then,(i) R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100(ii) P = $({A_2T_1 - A_1T_2}/{T_1 - T_2})$
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