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A student has to obtain 33% of the total marks to pass . He got 125 marks and failed by 40 marks. The maximum marks are :


Options:
A .  300
B .  500
C .  800
D .  1000
Answer: Option B

Let the maximum marks be `x`.

Then, 33% of `x` =  125 + 40  `hArr   323/100 x  =  165   hArr   x = ((165 xx 100)/(33))` = 500



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