A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
Options:
A . 12
B . 16
C . 24
D . 18
Answer: Option B Let he has solved correctly X no. of sums. Therefore incorrect no. of sums = 2X Now, X + 2X = 48 3X = 48 X = 16 sums he has done correctly.
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