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A semicircular sheet of paper of diameter 28 cm is bent to cover the exterior surface of an open conical ice-cream cup. The depth of the ice-cream cup is :
Options:
A .  8.12 cm
B .  10.12 cm
C .  12.12 cm
D .  14.12 cm
Answer: Option C
Slant height of the cup, l = Radius of sheet = 14 cm
Circumference of the base :
= Circumference of the paper sheet
= $$\left( {\frac{{22}}{7} \times 14} \right)$$  cm
= 44 cm
Let the radius of the base of the cone be r cm
$$\eqalign{
& \therefore 2\pi r = 44 \cr
& \Rightarrow r = \frac{{44 \times 7}}{{2 \times 22}} \cr
& \Rightarrow r = 7 \cr
& {\text{Height, h:}} \cr
& = \sqrt {{l^2} - {r^2}} \cr
& = \sqrt {{{\left( {14} \right)}^2} - {{\left( 7 \right)}^2}} \cr
& = \sqrt {147} {\text{ cm}} \cr
& = 7\sqrt 3 {\text{ cm}} \cr
& = 12.12{\text{ cm}} \cr} $$

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