A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Options:
A . 2.91 m
B . 3 m
C . 5.82 m
D . None of these
Answer: Option B Area of the park = (60 x 40) m2 = 2400 m2 Area of the lawn = 2109 m2 ∴ Area of the crossroads = (2400 - 2109) m2 = 291 m2 Let the width of the road be x metres. Then, 60x + 40x - x2 = 291 ⇒ x2 - 100x + 291 = 0 ⇒ (x - 97)(x - 3) = 0 ⇒ x = 3 m
Submit Comment/FeedBack