A rectangle has width a and length b . If the width is decreased by 20% and the length is increased by 10% , then what is the area of he new rectangle in percentage compared to 'ab' ?
New area = `(80/100 a xx 110/100 b) `
= `(4/5 xx 11/10 ab) = (22/25 ab)`
`:.` Required percentage = `(22/25 ab xx 1/ab xx 100)`% = 88%.
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