Question
A radio receiver antenna that is 2 m long is oriented along the direction of the electromagnetic wave and receives a signal of intensity 5× 10−16 W/m2. The maximum instantaneous potential difference across the two ends of the antenna is
Answer: Option A
:
A
I=12ϵ0CE20
⇒E0=√2Iϵ0C=√2×5×10−168.85=0.61×10−6Vm
Alsop E0=V0d⇒V0=E0d=0.61×10−6×2=1.23μV
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:
A
I=12ϵ0CE20
⇒E0=√2Iϵ0C=√2×5×10−168.85=0.61×10−6Vm
Alsop E0=V0d⇒V0=E0d=0.61×10−6×2=1.23μV
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