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A path of uniform width turns the inside of a rectangular field 38m long and 32m wide. IF the path occupies 600 m2 than the width of the path is
Options:
A .  3m
B .  5m
C .  8.75m
D .  10m
Answer: Option B


Area of the field = (38 x 32)m2 
Let the width of the path be x metres 
 Area with out path = (38-2x)(32-2x)m2 
 = 1216+4x2 -140x 
Area of the path = 1216 “(1216 +4x2 -140x) 
= 140x -4x2
140x -4x2 = 600 
=> 4x2-140x +600 =0 
=> x2 -35x +150 =0 
=> (x-30)(x-5)=0 
=> X =5 m



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