A number is first decreased by 10% and then increased by 10%. The number so obtained is 50 less than the original number. The original number is
Options:
A . 5000
B . 5050
C . 5500
D . 5900
Answer: Option A Answer: (a) Let the original number be x. $90/100x × 110/100 = x – 50$ ${99x}/100 =x - 50$ $x - {99x}/100 = 50$ $x/100 = 50 ⇒ x = 5000$ Using Rule 3, If an amount is increased by a% and then it is reduced by a% again, then percentage change will be a decrease of $a^2/100 %$
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