A number is decreased by 10% and then increased by 10% . The number s obtained is 10 less than the original
number . What was the original number ?
Let the original number be `x`
Final number obtained = 110% of (90% of `x`) = `(110/100 xx 90/100 xx x)` = `99/100 x`
`:.` `x - 99/100x = 10 hArr 1/100 x = 10 hArr x = 10 xx 100` = 1000.
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