A number consists of two digits such that the digit in the ten's place is less b

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A number consists of two digits such that the digit in the ten's place is less by 2 than the digit in the unit place. Three times the number added to $$\frac{6}{7}$$ times the number obtained by reversing digits equals 108. The sum of digits in the number is -

Options:

A . 8

B . 9

C . 6

D . 7

Answer: Option C

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