A man walking a the speed of 4 kmph crosses a square field diagonally in 3 minutes . The area of the field is :
Speed of the man = `(4 xx 5/18)` m.sec = `10/9` m.sec
Time taken = `(3 x 60) sec. = 180 sec.
Length of diagonal = (speed x time) = `(10/9 xx 180)` m. = 200 m.
Area of the field = `1/2 xx (diagonal)^2` = `(1/2 xx 200 xx 200) m^2` =` 20000 m^2`
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