Question
A man standing on a platform hears the sound of frequency 605 Hz coming from 550 Hz train whistle moving towards the platform. If the velocity of sound is 330 m/s. What is the speed of train?
Answer: Option A
:
A
Apparent Frequency is given by:
n′=n(v+v0v−vs)
605=550(330+0330−vs)
vs=30m/s
Was this answer helpful ?
:
A
Apparent Frequency is given by:
n′=n(v+v0v−vs)
605=550(330+0330−vs)
vs=30m/s
Was this answer helpful ?
Submit Solution