A man sells chocolates which are in the boxes. Only either full box or half a box of chocolates can be purchased from him. A customer comes and buys half the number of boxes which the seller had plus half box more. A second customer comes and purchases half the remaining number of boxes plus half a box. After this the seller is left with no chocolate boxes. How many chocolate boxes the seller had initially?
Options:
A . 2
B . 3
C . 4
D . 3.5
E . None of these
Answer: Option B The best way to go through the options Let there are initially 3 boxes then, 1st customer gets = $$\frac{3}{2}$$ + $$\frac{1}{2}$$ = 2 Remaining boxes = 3 - 2 = 1 2nd customer = $$\frac{1}{2}$$ + $$\frac{1}{2}$$ = 1 So, option B is correct.
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