A man lifts a luggage of 10kg from the ground and puts it on his head 1.7m above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity=10ms−2.
Options:
A .
150J
B .
170J
C .
180J
D .
200J
Answer: Option B : B Given: Mass, m=10kg, Acceleration due to gravity, g=10ms−2, Displacement, s=1.7m. Force F is calculated as F=m×g=10×10=100N Work done by the man on luggage=Force×displacement W=100×1.7=170J Hence, the required work done is 170J. It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of the earth.
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