A large field of 750 hectares is divided into two parts . The difference of he areas of the two parts is one -fifth of the average of the two areas. What is the area of the smaller part in hectares ?
Let the areas of the two pars be `x` and `(700 - x)` hectares respectively , then
`[x - (700 -x)]` = `1/5 xx [(x + (700 - x))/(2)]`
`hArr 2x - 700 = 70 2x = 770`
`hArr x = 385`.
so area of smaller part = (700 - 385) hectares = 315 hectares.
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