A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?
Volume of the large cube = (33 + 43 + 53) = 216 cm3.
Let the edge of the large cube be a.
Let the edge of the large cube be a.
So, a3 = 216 \(\Rightarrow\) a = 6 cm.
So, Required ratio = \(\left(\frac{6\times(3^{2}\times4^{2}\times5^{2})}{6\times6^{2}}\right)=\frac{50}{36}= 25:18.\)
