Answer: Option C
Let the radius of the hemispherical bowl be r cm
Then,
$$\eqalign{
& 2\pi r = 176 \cr
& \Rightarrow r = \frac{{176 \times 7}}{{2 \times 22}} \cr
& \Rightarrow r = 28 \cr} $$
Volume of liquid in the bowl :
$$\eqalign{
& = \frac{1}{2} \times \left( {\frac{2}{3} \times \pi \times 28 \times 28 \times 28} \right){\text{ c}}{{\text{m}}^3} \cr
& = \left( {\frac{2}{3} \times \pi \times 14 \times 28 \times 28} \right){\text{ c}}{{\text{m}}^3} \cr} $$
Volume of 1 glass :$$ = \left( {\frac{2}{3} \times \pi \times 2 \times 2 \times 2} \right){\text{ c}}{{\text{m}}^3}$$
∴ Required number of person :
$$\eqalign{
& = \frac{{{\text{Volume of liquid in the bowl}}}}{{{\text{Volume of 1 glass}}}} \cr
& = \left( {\frac{{14 \times 28 \times 28}}{{2 \times 2 \times 2}}} \right) \cr
& = 1372 \cr} $$