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A hemisphere of lead of radius 6 cm is cast into a right circular cone of height 75 cm. The radius of the base of the cone is :
Options:
A .  1.4 cm
B .  2 cm
C .  2.4 cm
D .  4.2 cm
Answer: Option C
Let the radius of the cone be R cm
Then,
$$\eqalign{
& \frac{1}{3}\pi \times {R^2} \times 75 = \frac{2}{3}\pi \times 6 \times 6 \times 6 \cr
& \Rightarrow {R^2} = \left( {\frac{{2 \times 6 \times 6 \times 6}}{{75}}} \right) \cr
& \Rightarrow {R^2} = \frac{{144}}{{25}} \cr
& \Rightarrow {R^2} = \frac{{{{\left( {12} \right)}^2}}}{{{{\left( 5 \right)}^2}}} \cr
& \Rightarrow R = \frac{{12}}{5} \cr
& \Rightarrow R = 2.4\,cm \cr} $$

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