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A district has 64000 inhabitants . If the population increases at the rate of `2 1/2`% per annum, then the number of

inhabitants at the end of 3 years will be.


Options:
A .  68911
B .  68921
C .  69200
D .  70000
Answer: Option B

Population after 3 years = 64000 x `(1 + (5)/(2 xx 100))^3` = `(64000 xx 41/40 xx 41/40 xx 41/40)` =  68921.



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