A cricketer, whose bowling average was 12.4 runs/wicket takes 5 wickets for 22 runs in a match, thereby decreases his average by 0.4. The number of wickets, taken by him before this match was :
Options:
A . 87
B . 105
C . 78
D . 95
Answer: Option D Answer: (d)Let the number of wickets before the last match be x. According to the question, 12.4x + 22 = (x + 5 ) × 12 ⇒ 12.4x + 22 = 12x + 60 ⇒ 12.4x – 12x = 60 – 22 ⇒ 0.4x = 38 ⇒ x = $38/{0.4}$ =$380/4$ = 95
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