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A cricketer has a certain average for 10 innings . In the eleventh inning , he scored 108 runs, there by increasing his

average by 6 runs. Hiss new average  is :


Options:
A .  48 runs
B .  52 runs
C .  55 runs
D .  60 runs
Answer: Option A

Let average for 10 innings be `x` . Then

`(10x + 108)/(11)`   =  `x` + 6  `hArr`  `11x` + 66 =  `10x` + 108    `hArr`  `x` =  42.

`:.`   New average =  `x` + 6 = 48 runs.



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