A cricketer has a certain average for 10 innings . In the eleventh inning , he scored 108 runs, there by increasing his
average by 6 runs. Hiss new average is :
Let average for 10 innings be `x` . Then
`(10x + 108)/(11)` = `x` + 6 `hArr` `11x` + 66 = `10x` + 108 `hArr` `x` = 42.
`:.` New average = `x` + 6 = 48 runs.
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