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A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
Options:
A .  49 m2
B .  50 m2
C .  53.5 m2
D .  55 m2
Answer: Option A
$$\eqalign{
& {\text{Area}}\,{\text{of}}\,{\text{the}}\,{\text{wet}}\,{\text{surface}} \cr
& = \left[ {2\left( {lb + bh + lh} \right) - lb} \right] \cr
& = 2\left( {bh + lh} \right) + lb \cr
& = \left[ {2\left( {4 \times 1.25 + 6 \times 1.25} \right) + 6 \times 4} \right]{m^2} \cr
& = 49\,{m^2} \cr} $$

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