A circular road runs around a circular garden. If the difference between the circumference of the outer circle and the inner circle is 44 m, the width of the road is :
Options:
A . 3.5 m
B . 4 m
C . 7 m
D . 7.5 m
Answer: Option C Let the radii of the outer and inner circle be R and r respectively Then, $$\eqalign{ & 2\pi R - 2\pi r = 44 \cr & \Rightarrow 2\pi \left( {R - r} \right) = 44 \cr & \Rightarrow \left( {R - r} \right) = \frac{{44 \times 7}}{{22 \times 2}} \cr & \Rightarrow \left( {R - r} \right) = 7 \cr} $$
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