A candidate who gets 20% marks in an examination fails by 30 marks but another candidate who gets 32% gets 42 marks more than the passing marks. Then the percentage of pass marks is :
Options:
A . 33%
B . 50%
C . 25%
D . 52%
Answer: Option C Answer: (c) Difference of percentages of maximum marks obtained by two candidates = 32% – 20% = 12% Difference of scores between two candidates = 30 +42 = 72 12% of maximum marks = 72 Maximum marks = ${72 × 100}/12$ = 600 Pass marks = 20% of 600 + 30 = 120 + 30 = 150 Required percentage = $150/600 × 100 = 25%$ Using Rule 22, An examinee scored m% marks in an exam and failed by p marks. In the same examination, another examinee obtained n% marks and passed with q more marks than the minimum, then ∴ Maximum marks = $100/(n -m) × (p + q)$
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