A candidate secured 30% marks in an examination and failed by 6 marks. Another secured 40% marks and got 6 marks more than the bare minimum to pass. The maximum marks are
Options:
A . 100
B . 120
C . 180
D . 150
Answer: Option B Answer: (b) Difference of percentage = (40 – 30)% = 10% Difference of marks = 6 + 6= 12 Since,10% of total marks = 12 Total marks = ${12 × 100}/10 = 120$ Using Rule 22, Here, m = 30%, n = 40%, p = 6, q = 6. Maximum Marks = $100/{(n - m)} × (p + q)$ = $100/{(40 - 30)} × (6 + 6)$ = $100/10 × 12 = 120$
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