A 1Ω resistance is in series with an ammeter which is balanced by 75 cm of

Question

1 Ω

resistance is in series with an ammeter which is balanced by 75 cm of potentiometer wire. A standard cell of 1.02 V is balanced by 50 cm. The ammeter shows a reading of 1.5A. The error in the ammeter reading

Options:

A . 0.002 A

B . 0.03 A

C . 1.01 A

D . no error

Answer: Option B
:
B

i p = \frac{V}{l} = \frac{1.02}{50}

Voltage across ammeter =

\frac{V}{l} l_{1}

= \frac{1.02}{50} \times 75 = \frac{1.02}{2} \times 3 = 0.51 \times 3

The true current

I_{A}^{1} = \frac{V_{A}}{R} = \frac{1.53}{1} I_{A}^{1} = 1.53 A E r r o r = I_{A}^{1} - I_{A} = 1.53 - 1.5 = 0.03 A

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