A 0.001 molal solution of [Pt(NH3)4cl4] in water had a freezing point depression of 0.0054. If Kf  for water is 1.80, the correct formulation for the above molecule is
Options:
A. [Pt(NH3)4Cl3]Cl
B. [Pt(NH3)4]Cl4
C. [Pt(NH3)4Cl2]Cl3
D. [Pt(NH3)4Cl2]Cl2

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Answer: Option D
: D

T=iKfm
i=TfKfm=0.00541.80×0.001=3
Thus complexproducesthreeionspermolecule.hence possiblecorrectformulais
[Pt(NH3)4Cl2]Cl2

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