Question
ΔABC has a circle centred on vertex C that passes through points A and E. If ∠ABC ≈ ∠DEC, AC = 1 and CD = x, what is the distance between E and B?
Answer: Option B
:
B
Since ∠DEC ≅ ∠ABC, it follows that ΔDEC ≈ ΔABC.
So, 1x=BE+11
⇒x(BE+1)=1
⇒(BE+1)=1x
⇒BE=1−xx
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:
B
Since ∠DEC ≅ ∠ABC, it follows that ΔDEC ≈ ΔABC.
So, 1x=BE+11
⇒x(BE+1)=1
⇒(BE+1)=1x
⇒BE=1−xx
Was this answer helpful ?
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