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Question
$${\left( {64} \right)^{ - \frac{2}{3}}} \times {\left( {\frac{1}{4}} \right)^{ - 2}}$$    is equal to ?
Options:
A .  1
B .  2
C .  $$\frac{1}{2}$$
D .  $$\frac{1}{{16}}$$
Answer: Option A

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