8% of the voters in an election did not cast their votes. In this election, ther

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8% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner by obtaining 48% of the total votes defeated his contestant by 1100 votes. The total number of voters in the election was :

Options:

A . 22000

B . 21000

C . 27500

D . 23500

Answer: Option C
Answer: (c)
Let the total number of votes be 100.
Number of uncast votes = 8
Number of votes polled = 92
Number of votes obtained by the winner = 48
Number of votes obtained by the loser = 92 – 48 = 44
If the difference of win be 4 votes, total voters = 100
When the difference be 1100 votes, total voters
= $100/4 × 1100$ = 27500
Using Rule 21,
The amount of acid/milk is x% in 'M' litre mixture. How much water should be mixed in it so that the percentage amount of acid/milk would be y%?
Amount of water = ${M(x – y)}/y$

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