Question
6th term in expansion of (2x2−13x2)10 is
Answer: Option B
:
B
Applying Tr+1 =nCrxn−rd for (x+a)n
Hence T6 =10C5(2x2)5(- 13x2)5
= - (10!5!5!)(32) (1243) = - 89627
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B
Applying Tr+1 =nCrxn−rd for (x+a)n
Hence T6 =10C5(2x2)5(- 13x2)5
= - (10!5!5!)(32) (1243) = - 89627
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