Answer: Option A
$$\eqalign{
& {\text{Let}}\,{\text{the}}\,{\text{length}}\,{\text{of}}\,{\text{the}}\,{\text{wire}}\,{\text{be h}} \cr
& {\text{Radius}} = \frac{1}{2}mm = \frac{1}{{20}}cm.\,{\text{Then}}, \cr
& \Rightarrow \frac{{22}}{7} \times \frac{1}{{20}} \times \frac{1}{{20}} \times h = 66 \cr
& \Rightarrow h = {\frac{{66 \times 20 \times 20 \times 7}}{{22}}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 8400\,cm \cr
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 84\,meters \cr} $$